trying to simplify an algorithm

Ian Molton spyro at f2s.com
Tue Mar 1 11:59:23 PST 2005


Bennett Todd wrote:

> But relational operators that _create_ booleans --- ==, !=, <, >, et
> al --- create 0 or 1, strictly.

Fair comment, I'd forgotten that. my other points stand, however :)



More information about the lfs-chat mailing list