trying to simplify an algorithm

Bennett Todd bet at
Tue Mar 1 05:52:47 PST 2005

> > More to the point though I think technically its broken. Im
> > fairly sure C only defines 0 to be false. *all* other values are
> > true, therefore you are relying on the compiler to use 1.

This comment bugs me every time it comes by.

Yes, when interpreting values in as booleans, C defines zero ==
false, nonzero == true.

But relational operators that _create_ booleans --- ==, !=, <, >, et
al --- create 0 or 1, strictly.

So without commenting on the overall correctness or desireability
of this construction, I think the above claim is not correct for
standard C. The use of relops seems correct to me.

And decomposing the expression, it really looks strictly correct to

	( a+b+c == 180 ) * (a>0) * (b>0) * (c>0) *
	( 1 + (a==b) + (a==c) + (b==c) );

The whole thing is a product of 5 terms. The four on the first line
are all relops, 0 or 1, if any of 'em are zero the whole expression
is zero, and they constitute sanity-checking the inputs. It's a
triangle if all those conditions are true, i.e. all == 1.

The final term, on the second line, is 1, 2, or 4, as no angles
are equal, one pair of angles are equal, or all angles are equal,

Type-punning booleans with arithmentic integers may be naughty in
higher-level languages that have distinct boolean types, but in C
relops produce integers, with deterministic values.

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